Find two points on the graph of the parabola other than the vertex and x intercepts

Question

a(x)= x² +7x +12

Answer 1

I agree plug values in for x

I would choose 1. And -1

a(1) = (1)^2 + 7(1) + 12 =

1 + 7 + 12 = 20. (1,20)

a(-1) = (-1)^2 + 7(-1) + 12

1 - 7 + 12 =6. (-1,6)

Answer 2

Since I get to pick the points, I want to pick ones that are easy.

x=0 and x=1 Plug these values in for x and solve for y.

a(x)= x² +7x +12

a(0)= (0)² +7(0) +12

a(0)=12

Point 1: (0,12) This is the y intercept, directions only say you can't use the x intercepts.

a(1)= (1)² +7(1) +12

a(0)=1+7+12

a(0)=20

Point 2: (1,20)