Discriminat:
b^2 - 4ac > 0 two real solutions
b^2 - 4ac = 0 one real solution
b^2 - 4ac < 0 no real solutions
a = -5
b = 8
c = -3
(8)^2 - 4(-5)(-3)
64 - 60 = 4
therefore two real solutions
Jack F.
asked 08/07/20Discriminat:
b^2 - 4ac > 0 two real solutions
b^2 - 4ac = 0 one real solution
b^2 - 4ac < 0 no real solutions
a = -5
b = 8
c = -3
(8)^2 - 4(-5)(-3)
64 - 60 = 4
therefore two real solutions
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