A hunter is using a snowmobile to drag a 20.0-kg sled up a wet, snowy hill that forms an angle of 25.0° with the horizontal. The coefficient of kinetic friction for the

Question

A hunter is using a snowmobile to drag a 20.0-kg sled up a wet, snowy hill that forms an angle of 25.0° with the horizontal. The coefficient of kinetic friction for the sled on wet snow is 0.140. Calculate the force the snowmobile must exert to accelerate the sled at 2.00m/s^2.

a.) 24.9 N [uphill]

b.) 82.8 N [uphill]

c.) 148 N [uphill]

d.) 196 N [uphill]

Please show work

Thank you

Answer 1

Ricky

The force down the slope on the sled is mg sin α (due to gravity ) + k mg cos α (force of kinetic friction).

α is the angle of inclination, m the mass, g acceleration due to gravity = 9.8 m/s/s. k coefficient of kinetic friction.

For an acceleration of 2 m/s/s up the slope we need net force up the slope = ma = 2m.

So if F is the applied force : F - mg sin α - kmg cos α = 2m

So you can solve this for F (you know m, g, α, k).

Left for you as an exercise

Mike