in a series circuit, the voltage provided by the battery, VT, is 112 V, and the resistances R1 and R2 are 20.0 Ω and 60.0 Ω, respectively. The voltage across R1 is 14 V.

Question

in a series circuit, the voltage provided by the battery, VT, is 112 V, and the resistances R1 and R2 are 20.0 Ω and 60.0 Ω, respectively. The voltage across R1 is 14 V.

(a) What is the current flowing through the circuit? (b) What is the resistance R3?

Answer 1

its a series circuit, so we know

1) 112V = (R₁ + R₂ + R₃) x Current

because its series, we know the current is the same everywhere, so the current through R1 = current through rest of the circuit. This means...

2) Current = 14V/R₁

plug in R1, and you have your answer for (a)

for (b), look at equation 1). plug in what you get for current, solve for R3