Edward C. answered 02/10/15
Tutor
5.0
(438)
Caltech Grad for math tutoring: Algebra through Calculus
The sum of all the probabilities must be 1
Let P(3) = X
Then P(6) = P(5) = P(2) = X
P(4) = 4X
P(1) = 2P(4) = 2(4X) = 8X
So X + X + X + X + 4X + 8X = 1
16X = 1
X = 1/16
I don't know what w3, w4 and w1 represent, but
P(3) = X = 1/16
P(4) = 4X = 4/16 = 1/4
P(1) = 8X = 8/16 = 1/2