SURENDRA K. answered 07/13/14
An experienced,patient & hardworking tutor
Maaria Z.
asked 03/13/13I have this question regarding set theory and probability that i am struggling on:
Q: A group of international students take part in a survey on the nationality of their parents.
E= English Parent
F= French parent
n(ξ) = 50, n(E) = 15, n(F )= 9, n(E U F)' = 33
(1) Find n(E ∩ F)
(2) Find n(E' U F)
(3) A student is chosen at random. Find the probability that this student has an English parent and a French parent.
(4) A student who has a French parent is chosen at random. Find the probability that this student also has an English parent.
Thankyou so much for any help !
SURENDRA K. answered 07/13/14
An experienced,patient & hardworking tutor
Luke B. answered 03/13/13
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First thing to do is draw a Venn diagram. It will help tremendously.
If n(E U F)' = 33, then n(E U F) = 50 - 33 = 17, because n(E U F) + n(E U F)' = n(total).
We also know that n(E U F) = n(E) + n(F) - n(E ∩ F). Substitute values to get 17 = 15 + 9 - n(E ∩ F). Solve for n(E ∩ F) and get n(E ∩ F) = 7.
n(E' U F) is the number of students without an English parent plus the number of students with a French parent, which is the total number of students minus the number with an English parent, plus the number with a French parent: n(total) - n(E) + n(F) = 50 - 15 + 9 = 44.
Probability of a student with an E and and F is the probability of the union of E and F.
For the last one, it will be the intersection of E and F. I highly recommend you draw a Venn diagram and work this through!
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Maaria Z.
Thankyou so much.
03/13/13