Cara Marie M. answered 09/29/14
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Math Major, Pursing PhD in Math, with 10+ Years of Teaching Experience
The way the question is written, students can be divided into 4 groups:
1) Own a cat (can also own a dog, but don't need to) -- 8
2) Own a dog (can also own a cat, but don't need to) --15
3) Own both a dog and a cat -- 5
4) Own neither a dog nor a cat -- ??
Right now, we have students who are double counted. For example, students who only both a cat and a dog are included in the number of students who own a cat. Therefore, we need to find the number of students who own only a cat and only a dog. To do so, you subtract the number of students who own both a cat and a dog (5) from the number of students who own a cat (8) or own a dog (15).
8 - 5 = 3 students own only a cat
15 - 5 = 10 students own only a dog
5 students own both a cat and a dog.
Now, no students are double counted.
We know that there are 30 students total. If we add up the number of students who own only a cat, only a dog and both a cat and a dog, we get 3 + 10 + 5 = 18 students.
Thus, the number of students who own neither a cat nor a dog is:
30 - 18 = 12 students