Tom K. answered 07/22/20
Knowledgeable and Friendly Math and Statistics Tutor
b^2 = (1-e^2)a^2 = (1-1/4)a^2 = 3/4a^2
Then, as the ellipse passed through (1, 3) and is centered at the origin
x^2/a^2 + y^2/b^2 = 1
1^2/a^2 + 3^2/(3/4a^2) = 1
13/a^2 = 1
a^2 = 13
b^2 = 3/4a^2 = 39/4
x^2/13 + 4y^2/39 = 1