Sidney P. answered 07/24/20
Minored in physics in college, 2 years of recent teaching experience
You may have already answered question 4 itself, but here goes as a check (I need some of this anyway to have a value for spring constant k): Given amplitude A = 1.5 m, mass = 0.0278 kg, ω = 2πf = 21.4 rad/s (coefficient of t in sin expression), then f = 3.406 Hz, T = 1/f = 0.2936 s. For spring SHM, ω = √(k/m) so k = mω2 = 12.73 N/m.
Max velocity = Aω = 32.1 m/s. Total energy Et = ½ m vmax2 = ½ k A2 = 14.32 J.
Halfway to maximum amplitude, spring potential energy Es = ½ k (½ A)2 = 3.58 J, and KE = the remaining 10.74 J. The speed at this point comes from v2 = 2 KE/m = 773, v = 27.8 m/s.