Given that sin(θ)=11/12, and θ is in Quadrant II, what is cos(2θ)?

Question

give answer as a fraction

Answer 1

As you are given sin, cos(2θ) = 1 - 2 sin²(θ). Note that it does not matter what quadrant you are in in doing this calculation.

1 - 2(11/12)² = 1 - 121/72 = -49/72