The doubling period of a bacterial population is 10 minutes. At time t = 100 minutes, the bacterial population was 60000.

Question

What was the initial population at time ?

Find the size of the bacterial population after 4 hours.

Answer 1

60000 = a₀(2)^100/10

60000 = a₀(2)¹⁰

60000 = 1024a₀

58.59 = a₀