sum -to-product to rewrite the following expression as a product sin(𝜋 + 𝜃) + sin(𝜋 − 𝜃)

Question

sum -to-product to rewrite the following expression as a product   sin(𝜋 + 𝜃) + sin(𝜋 − 𝜃)

Arthur D. · Accepted Answer

sin(∏+x)+sin(∏-x)     I'm using x for θsinΠcosx+cosΠsinx+sinΠcosx-cosΠsinxsinΠ=0 and cosΠ=-1therefore, 0-sinx+0-(-sinx)=0-sinx+0+sinx=0

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