
Yefim S. answered 05/03/25
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Image in 1st lens located at f = F1 = 20 cm. Thes for second lense we have d2 = - (20 - 12) = - 8 cm and by formul 1/F2 = 1/d2 + 1/f2; - 1/6 = - 1/8 + 1/f2; f2 = - 24 cm. So, image we have in front of second lenz in 24 cm from it