Dr Gulshan S. answered 07/04/20
Physics Teaching is my EXPERTISE with assured improvement
- In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression,
x = 5.00cos(4t+(pi/6))
where x is in centimeters and t is in seconds
At t = 0, find acceleration of the piston
2.A light, rigid rod of length ℓ = 1.00 m
joins two particles, with masses m1 = 4.00 kg
and m2 = 3.00 kg,
at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). the speed of each particle is 8.00 m/s. What would be t
he new angular momentum of the system (in kg · m2/s) if each of the masses were instead a solid sphere 13.5 cm in diameter? (Round your answer to at least two decimal places.)
As 1 has already been answered, here is answer to problem 2
Angular momentum= I *w where I is moment of inertia
and w= angular velocity
I in this case = m1 r1 2 +m2 r22
Plug in m1 and m2 and r1 = 0.5 m =r2
Now w = v/r =8/0.5, Get Angular momentum
For solid sphere use I = 2/5 (mr2 ) for each sphere and then move axis to center using Parallel axis theorem
Ieffective = I + md2