
Jeremiah T. answered 07/02/20
Tutor
New to Wyzant
Award Winning Tutor for Algebra and Precalculus
For me finding the answer is easier if I substitute y for u(x).
q(x) = p(y)
p(y) = 9y - 5
6√5 = 9y - 5
(6√5 + 5)/9 = y = u(x)
So u(x) is a little more than 2.