Kinematics Horizontal Motion Problem: Please Help!!

Question

A projectile is fired at 28 m/s at an angle of 33 degrees with the horizontal from a point 75 m above the ground. How long did it take for the projectile to hit the ground below? How far did the projectile travel horizontally?

Answer 1

v = 28 m/s

theta = 33 deg

h = 75 m

Vx = 28cos(33)

Vy = 28sin(33) - 9.81*T

X = 0 + Vx*T +0.5*0*T

X = 28cos(33)T

Y = 75 + [ 28sin(33) - 9.81*T]*T -0.5*9.81*T^2

Find the roots of Y(T) these values are the time when hits ground

T = 5.7625 s

-----> Time take = 5.7625 seconds

X = 28cos(33)(5.7625)

-------> Distance = 135.3194 m

Max height = 86.85632 m

Equation of function models path

Y(T) = -0.0089 T^2 + 0.6494 T + 75 meters

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