A FEMALE HAMMER SHOOTER

Question

A female hammer shooter successfully completed her movement within a radius of 1.0675 m, turning 3 turns in 1 second in the competition. What is the centripetal force required to keep the hammer in circular motion at this speed (Hammer: 4 kg)?

Note: For this question; Use 4 digits after the comma in the operations to be performed.

Answer 1

Fc = (m/r)v^2

r = 1.0675m

w = 3rev/1sec *2pi

v = rw

Fc = (m/r)(rw)^2 = [(4/1.0675)(1.0675*)]... plug n chug