Sidney P. answered 06/20/20
Minored in physics in college, 2 years of recent teaching experience
a) Voltage V = current I * resistance R, so 125 = 24*I and I = 5.21 Amps.
b) Power P = I*V = (5.21)(125) = 651 Watts = 0.651 kW. For 12.5 hours, total energy = P*t = (0.651)(12.5) = 8.14 kWh. At $0.10 per kWh, then cost is (8.14)(0.10) = $0.81.
c) Another equation for power is P = V2 /R. We're given that P = 1.8 kW = 1,800 W. Find R from the Canadian parameters: R = V2 /P = (120)2 / (1,800 W) = 8.0 Ω of resistance. When we go where V = 240 volts, then power P' = (240)2 /(8.0) = 7,200 W = 7.2 kW (4 times more power than in Canada).