Ram S.

asked • 06/19/20

Homework I need the right answer

A 30 kg box moving at a speed of 4 m/s is brought to a stop in 0.6 sec. What force is required? Show your work.?

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Sidney P. answered • 06/19/20

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The acceleration in bringing the box to a stop is: a = (vf - vi) / Δt = (0 - 4)/0.6 = -6.67 m/s2. The force is then calculated from Newton's 2nd Law: Fnet = m*a = (30) (6.67) = 200 N.

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Sidney P.

Technically the force is -200 N, indicating that it of course is opposite to the direction of motion.
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06/19/20

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