The voltage produced in coil 2 is:
V2 = -d/dt (N2Φ21)
= -d/dt (MI1)
V2 = -M * dI1/dt
Which means dI1 / dt ≈ ΔI1/Δt if our time lapse is finite
M = -V2Δt / ΔI1
= -(9 V)(1e-3 s) / (5 A)
= 1.8e-3
Muhammad S.
asked 06/18/20Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is switched off in 1.00 ms, inducing a 9.00 V emf in the other. What is their mutual inductance?
The voltage produced in coil 2 is:
V2 = -d/dt (N2Φ21)
= -d/dt (MI1)
V2 = -M * dI1/dt
Which means dI1 / dt ≈ ΔI1/Δt if our time lapse is finite
M = -V2Δt / ΔI1
= -(9 V)(1e-3 s) / (5 A)
= 1.8e-3
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