Sava D. answered 06/11/20
Math master degree tutor with good understanding of precalculus
The setup for this problem is as follows:
- We choose variables: a for adults, s for seniors and c for child.
- Then we have two relationships:
total number of tickets sold:
a + s + c = 500 - 57
total sold:
8a + 7s + 5c = 2756
The third relationship is the number of adult and child tickets.
2c = a.
Translating this into a system looks like this:
a + c + s = 443
8a + 5c + 7s = 2756
a - 2c = 0.
Trying to solve the above system, it turns out it is inconsistent, which means there is no solution that satisfies all the three requirements. However, if we flip the third requirement, twice as many adult tickets sold as child tickets sold ( 2a = c), you can get definite answer. (a = 115, c = 230, s = 98).
Corrected system is
a + c + s = 443
8a + 5c + 7s = 2756
2a - c = 0.
If you need help with the above system, let me know so I can provide step by step answer.
Sava D.
06/11/20