An electrostatic force of 20. newtons is exerted on a charge of 8.0x10^-2 coulomb at point P in an electric field. What is the magnitude of the electric field intensity at P?

Answer 1

Hi Ashley,

The electrostatic force = 20N

Charge q = 8*10^-2 C

Electric field intensity by definition is Force per unit charge

E = Force / charge = F/q

= 20N /8*10^-2 C

= 2.5*10² N/C