A rolling ball moves from x_1= 8.4 cm to x_2 = -4.0 cm during the time from t1 = 3.8 s to t_2 = 6.7 s - what is its average velocity over this time interval?

Question

PLS ANSEWR WITHIN 10 MINUTES PLEASE

Answer 1

Average velocity is the change in distance divided by the change in time.

V_avg = Δx/Δt = (-4.0 - 8.4)/(6.7 - 3.8) = -12.4/2.9 = -4.2759 cm/s = -4.3 cm/s (using 2 significant figures)