How much force is needed to support a 106−kg iron anchor when it is submerged in seawater? (Hint: First find the anchor's volume.) Round your intermediate steps to three decimal places. N

Answer 1

How much force is needed to support a 106−kg iron anchor when it is submerged in seawater? (Hint: First find the anchor's volume.) Round your intermediate steps to three decimal places. N

Archimedes' principle states that, when a body is partially or completely immersed in a fluid, it experiences an apparent loss in weight that is equal to the weight of the fluid displaced by the immersed part of the body.

Density of iron = 7,874 kg/m³ = m/v

volume of anchor is 106/7874 = 0.013 m3. Volume of water displaced is equal to the volume of the anchor.

Weight of water displaced = m = v x density =0.013 x 1000 kg x 9.81m/s2 = 132N.

Weight of anchor in air = 106 x 9.81 = 1040 N

Weight of anchor in water = 1040 - 132 = 908N. So the force needed to support the anchor in water is 908N