Please round your answer to the nearest integer. A 2,267 lb car is equally supported by its 4 tires, which are inflated to a pressure of 1 bar. What area of each tire is in contact with the road?

Answer 1

P = F/A = mg/A

Eq 1

A = mg/P

Conversions

2267 lb * (1 kg/2.2 lb) = 1030.45 kg

1 bar = 1e5 Pa

Using eq. 1

A_{all tires} = (1030.45 kg)(9.8 ms^-2) / 1e5 Pa = 0.1 m²

A_{1 tire} = 1/4 (A_all) = 0.025 m²