Conservation of Energy Question

Question

A 2.25 kg ball is thrown upward from ground level with an initial velocity of 12.0 m/s. What is the maximum height reached by the ball? Remember to state your givens for initial and final.

Answer 1

For this question, all you need to use is the kinematic equation...

v² = v_o² + 2aΔx

You are given that v_o is 12.0 m/s. You also know that v (which is final velocity) is 0 since the ball is at its maximum height. Acceleration (a) is -9.8 m/s². The acceleration is negative since gravity is acting upon the ball in the downward direction while the ball is moving upward. So once you plug all these values in, you then just solve for Δx...

0² = 12.0² + 2(-9.8)Δx

-144 = -19.6Δx

7.35m = Δx