Arturo O. answered 06/04/20
Experienced Physics Teacher for Physics Tutoring
vx = v0cosθ = 20cos50° = 12.86 m/s
vy = v0sinθ - gt = 20sin50° - 9.8(7)m/s = -53.28 m/s
v = √(vx2 + vy2) = √[(12.86)2 + (-53.28)2] m/s = ? m/s
Ian C.
asked 06/04/20a rocket is launched at 20m/s at an angle of 50 degrees horizontally. It blows up 7 seconds after it took off. find the speed of the projectile before it blew up.
Arturo O. answered 06/04/20
Experienced Physics Teacher for Physics Tutoring
vx = v0cosθ = 20cos50° = 12.86 m/s
vy = v0sinθ - gt = 20sin50° - 9.8(7)m/s = -53.28 m/s
v = √(vx2 + vy2) = √[(12.86)2 + (-53.28)2] m/s = ? m/s
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