please answer this :

Question

A parallel-plate capacitor has a plate area of 0.3 m2 and a plate separation of 0.1 mm. If the

charge on each plate has a magnitude of 5  10^–6 C then the force exerted by one plate on the

other has a magnitude of about:

Answer 1

Force on either plate of a capacitor due to opposite charge on the other plate of a parallel plate capacitor is given as

F= q²/2A€₀

_{Here q= charge on each plate of parallel plate capacitor}

_{A = Area of each plate}

_{Plug in the values}