Dr Gulshan S. answered 06/05/20
PhD In Physics and experience of teaching IB Physics and Math High sc
For a conducting sphere the charge is uniformly distributed over its surface and for finding field just outside the surface the equivalent charge may be supposed to be located at the center of sphere
So
E = KQ/r2
Where K = 9*109
For just outside r = R = radius of sphere
E = 9*109 * (10-9 ) / (0.01)2 N/C
= 9* 109 * 10 -9/ 10 -4 N/C

Dr Gulshan S.
06/05/20