William W. answered 06/04/20
Top Pre-Calc Tutor
x3 - 8 = (x - 2)(x2 + 2x + 4)
So when we divide by (x - 2), the "x - 2" 's will cancel leaving limit as x approaches 2 of x2 + 2x + 4
Now, we can plug in x = 2
22 + 2(2) + 4 = 3 + 4 + 4 = 12
Valesia S.
asked 06/04/20As x approaches 2
(x3-8)/(x-2)
William W. answered 06/04/20
Top Pre-Calc Tutor
x3 - 8 = (x - 2)(x2 + 2x + 4)
So when we divide by (x - 2), the "x - 2" 's will cancel leaving limit as x approaches 2 of x2 + 2x + 4
Now, we can plug in x = 2
22 + 2(2) + 4 = 3 + 4 + 4 = 12
Mark R. answered 06/04/20
PhD Physics Tutoring, UT/Harvard
Hello Velesia,
There are a few different ways to do this, including graphing the function, factoring out the (x-2), and using the technique from calculus known as l'Hospital's rule.
Since you listed "calculus" in the description, I've uploaded a short video which will walk you through the steps of using l'Hospital's rule. It looks like William W. already explained how to factor and then plug in two, and that works just as well for this problem, but your teacher will probably ask you to use l'Hospital's rule on things that can't be factored as well.
Best,
Mark R.
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