find the output voltage and current through I1, I3

Question

A circuit has three resistances R1 =1 Ω, R2 = 5 Ω, and R3 =2 Ω, and one battery supply and an ammeter.

R2 and R3 are connected in parallel combination, and they both are connected with R1 in series combination, and the ammeter is connected with R2. The ammeter measures the current running through R2 as 2.00 A.

Knowing that I2 = 2.00 A, use Kirchhoff’s Laws on the circuit and find the currents through R1 and R3

and find the output voltage of the power source. ( I1 = ? , I3 = ? , V = ? )

PLEASE SOLVE WITH STEPS 😊

Answer 1

The voltages across R₂ and R₃ are the same, so

I₂R₂ = I₃R₃ ⇒

I₃ = I₂R₂ / R₃ = (2)(5) / (2) A = 5A

I₁ = I₂ + I₃ = (2 + 5) A = 7A

V₁ = I₁R₁ = (7)(1) v = 7v

Voltage across entire network:

Either of the 2 equations below will give it.

V = I₂R₂ + V₁ = [(2)(5) + 7] v = 17v

V = I₃R₃ + V₁ = [(5)(2) + 7] v = 17v