help me with this please

Question

find the solution for X that are in the interval [0,2pi)

sin²X -2sinX=0

Answer 1

sin²X -2sinX=0

Factor out sinX

sinX (sinX - 2) = 0

sinX = 0 or sinX - 2 = 0 (sin X = 2 is not possible it's outside of the [-1,1] range)

X = 0, ∏