Tom K. answered 06/03/20
Knowledgeable and Friendly Math and Statistics Tutor
cos(arc tan sqrt(3) - arccos(x)) =
cos(arctan sqrt(3)) cos(arccos(x)) + sin(arc tan sqrt(3)) sin(arccos(x))
arctan sqrt(3) = π/3; cos(π/3) = 1/2, and sin(π/3) = √3/2
cos(arccos(x)) = x
sin(arccos(x)) = √(1-x2); since arccos takes on values from 0 to π, sin is non-negative, so we only have the positive square root here.
Therefore, cos(arctan sqrt(3)) cos(arccos(x)) + sin(arc tan sqrt(3)) sin(arccos(x)) =
1/2x + √3/2 * √(1-x2) or 1/2 x + 1/2 √(3-3x2 ) Note that the domain of x is [-1,1], as that is the domain for which arccos is defined - cos can only have values between -1 and 1