Daniel D. answered 05/31/20
College Senior Studying Prehealth with Computer and Data Science
It turns out that you don't actually need the mass of the eraser to determine the coefficient of friction here. You're given that the eraser moved 2.09m over 1.44s while a frictional force was applied on it, so the object is undergoing constant deceleration. You can determine this deceleration by using one of the kinematic equations.
Δx = vot + 1/2at2)
Δx = 2.09
t = 1.44
The variable vo is 0 since the eraser's final velocity was 0. Although vo denotes initial velocity of the object (which wasn't actually 0), we can assume this value is 0 because whether the object is accelerating from 0 to whatever that velocity was, or decelerating from that velocity to 0 (which is the current scenario), Δx is the same in both cases. Therefore, to make life a bit easier, we assume it's the scenario where the object is accelerating rather than decelerating, that way we can assume that vo is 0. Therefore, we get.
2.09 = 1/2a(1.44)2
We then solve for a and get a = 2.02. Newton's second law says f = ma, so f = m(2.02). In this case, f represents the frictional force, which we know can also be found from the formula ...
ffric = µfn
fn is the normal force of the object
Therefore we have an equality ...
ffric = m(2.02) = µfn.
Normal force is calculated by multiplying the mass of an object by 9.8, which is the acceleration of gravity. Therefore...
m(2.02) = µ(9.8m).
Since m appears on both side of the equation, it cancels out, so we have...
2.02 = µ*9.8
Solving for µ, we get ...
µ = 2.02/9.8 = 0.206