Shane B. answered 08/11/21
M.D. and M.S. in Pharmacology, 4yr working pharmacology research
68 y/o male on oral procainamine 750mg q6hr.
If Css = 1.5mg/L we want to calculate the dose necessary to reach Css= 2.5mg/L.
We need to use our PK equations to solve this.
MD = (Cl * Css * t) / f
We can use algebra to make a new equation
MD = (Cl * Css * t) / f
0 = (Cl * Css * t) / (f * MD)
then we can make two equations equal to each other and solve for the missing maintenance dose.
(Cl * Css1 * t) / (f * MD1) = (Cl * Css2 * t) / (f * MD2)
Dosing interval is the same and bioavailability won't change in the therapeutic range so we can cancel those out. Clearance will be the same.
( Css1) / (MD1) = (Css2) / (MD2)
(1.5mg/L) / (750mg) = (2.5mg/L) / (X mg)
x = 1250mg
technically it will take 5 half-lives to reach the new steady state this way