Jerry V. answered 05/15/20
Purdue Engineering Student with Extensive Application of Trigonometry
The best way to start this problem, in my opinion, is to set up a "T-chart" with x values on the left, and corresponding f(x) values on the right. Let's do that.
Let's look at f(x) = x2 first. Let's pick some test values of x. I am going to pick 0, 1, 2, and 3. Let's put that in to the x column below.
x | f(x)
0 |
1 |
2 |
3 |
Now we want to use the given function to evaluate the f(x) values. In this case, it is pretty simple: just square each x value and place it in the right f(x) spot. We get:
x | f(x)
0 | 0
1 | 1
2 | 4
3 | 9
Let's do the same for f(x) = x3. Set up the T-table and pick test values.
x | f(x)
0 |
1 |
2 |
3 |
To evaluate, simply cube each of the x values and place it in the right f(x) spot.
x | f(x)
0 | 0
1 | 1
2 | 8
3 | 27
Now let's look at the f(x) = square root of x, commonly written as f(x) = sqrt(x). We will follow the same procedure as above, but we should be careful what x values we pick; we want the x values to turn into nice whole number f(x) values. We should pick numbers that are perfect squares, so that when we take the square root, the corresponding value is a positive integer. Let's pick the first 3 perfect squares: 1, 4, and 9.
x | f(x)
1 |
4 |
9 |
When we take the square root of these, we get:
x | f(x)
1 | 1
4 | 2
9 | 3
Finally, we have f(x) = absolute value of x, commonly written as f(x) = abs(x). If we recall what absolute value does, we remember that an absolute value turns negative numbers to positive numbers (for example abs(-7) = 7) and keeps positive numbers as positive numbers (for example abs(7) = 7). We now see that it will be important to pick a few negative numbers to see what the graph will look like. Let's pick -2, -1, 0, 1, and 2 to be our x values.
x | f(x)
-2 |
-1 |
0 |
1 |
2 |
Let's fill in the f(x) by taking the absolute value:
x | f(x)
-2 | 2
-1 | 1
0 | 0
1 | 1
2 | 2
Now that we have these values, match the points that you found to each graph. For example, the graph for f(x) = x2 will contain the points (0, 0), (1,1), (1,4), (1,9).
As you gain more experience you will notice patterns with the graph. For example, absolute value graphs have a sharp bump. Similarly, x3 rises more quickly than x2 which rises more quickly than sqrt(x).
Hope this helps!