Select all that apply

Question

(A). Which of the following functions have 3 in their domain? (Select all that apply)

h(x)= square root of x-6

f(x)= x²-3x

g(x)= x-3/x

(B). For the functions from part (A) that do have 3 in their domain, find the value of function at 3.

(If 3 is not the domain, enter unrefined)

f(x)= x²-3x ?

g(x)= x-3/x ?

h(x) = square root of x-6

Answer 1

Hi Mj,

Try doing Part B first. If the function has a value at 3, then 3 is in the domain of the function.

For example, 3 is in the domain of f(x) = x^2 + 1 because f(3) = 3^2 + 1 = 9 + 1 = 10.

3 is not in the domain of g(x) = 1/(x-3) because attempting to evaluate g(3) results in division by 0 which is undefined.