John M. answered 05/15/20
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x=t - 1, y = t^2 -2t
t= x+1
y = (x+1)2 - 2(x+1)
y = x2 + 2x + 1 -2x -2
y = x2 -1
Laura B.
asked 05/15/20From these answers
a) y = x^2 -1
b) y = x^2 + 1
c) y = -x^2 -1
d) y = -x^2 + 1
John M. answered 05/15/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
t= x+1
y = (x+1)2 - 2(x+1)
y = x2 + 2x + 1 -2x -2
y = x2 -1
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