Arthur D. answered 05/12/20
Mathematics Tutor With a Master's Degree In Mathematics
5000=500(1+80%)^t
10=(1.8)^t
log(10)=log((1.8)^t)
1=t*log(1.8)
1=t*0.2552725051
t=1/0.2552725051
t=3.917 days
Ari B.
asked 05/12/20Using the formula I think A=P (1+r) ^t or A=Pe^rt
Arthur D. answered 05/12/20
Mathematics Tutor With a Master's Degree In Mathematics
5000=500(1+80%)^t
10=(1.8)^t
log(10)=log((1.8)^t)
1=t*log(1.8)
1=t*0.2552725051
t=1/0.2552725051
t=3.917 days
Arthur D. answered 05/12/20
Mathematics Tutor With a Master's Degree In Mathematics
5000=500(1+80%)^t
10=(1.8)^t
log(10)=log(1.8)^t
1=tlog(1.8)
t=1/log(1.8)
t=1/(0.2552725051)
t=3.917 days
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