Inactive Tutor answered 05/24/20
Tutor
New to Wyzant
sinA = 2/√13
cosA = √(1 - sin2A) = √(1 - 4/13) = √(9/13) = 3/√13
tanA = sinA / cosA = (2/√13) / (3/√13) = 2/3
Joey M.
asked 05/11/20Inactive Tutor answered 05/24/20
sinA = 2/√13
cosA = √(1 - sin2A) = √(1 - 4/13) = √(9/13) = 3/√13
tanA = sinA / cosA = (2/√13) / (3/√13) = 2/3
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