2sec^x-2sec^2x sin^2x

Question

i've done problems like this before, but i was always able to change a term to cancel out something

Answer 1

2sec^2(x) - 2sin^2(x)/cos^2(x)

=2sec^2(x) -2tan^2(x)

=2[sec^2(x) -tan^2(x)]

=2(1)

=2

Answer 2

2sec^x-2sec^2x sin^2x

= 2sec^x(1-sin^2x)

= 2sec^x cos^2x

= 2 <==Answer