A 27 kg crate is initially sliding at 18 m/s when it reaches a surface that applies 65 N of friction. How far does the crate slide by the time it stops?

Answer 1

v² - v₀² = 2ax

x = (v² - v₀²) / (2a)

v = 0 (full stop)

x = - v₀² / (2a)

a = F/m = -65 N / (27 kg) = ? m/s² (note a is negative)

v₀ = 18 m/s

Plug these numbers into the equation for x, with the negative sign for a, and get x (positive) in units of meters.