Solve 4tanx−4sqrt3 = 0 on the interval (0, 2pi)

Answer 1

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Answer 2

4tanx - 4√3 = 0, (0, 2π)

when we solve for tanx we get

4tanx = 4√3 =

tanx = (4√3)/4 =

tanx = √3, within the above interval where does tanx equal rad 3???

arctan(√3) = x = π/3 & 4π/3