Part 1
y=b/x2 => dy/dx=-2b/x3
The equation of the tangent line is y=(b/4)x+(21/4)
Therefore
-2b/x3 = b/4 and x=-2
Now the tangent line and the curve must meet at the point of tangency; therefore
(b/4)x+(21/4) = b/x2
Substitute the value of x into this equation and solve for b
Part 2
The first derivative is (x+1)-2
The 2nd is -2(x+1)-3
And this establishes the pattern
Part 3
What is your question?
Part 4
Use the chain rule.
It is a messy problem but straightforward...just be careful with algebra.

Paul M.
04/30/20
Hilary T.
Thank you so much, sir. For question 3, i have to find the value(s) for k so that the the given equation can exist: “(5x^2+8x-4) / (x^2-3x-K)” as x approaches 3.04/30/20