
Yefim S. answered 05/02/20
Math Tutor with Experience
If we consider semicircle-section with y-coordinate equel y then radius r of this section will be r = (16 - y2)1/2.
Then area A of this section A = πr2/2 = π(16 - y2)/2. Then volume V = ∫-44 π(16 - y2)/2.dy = π∫04(16 - y2)dy = π(16y - y3/3)04 = π(64 - 64/3) = 128π/3.
Answer is 1)