5000 = 4000(1 + 0.0875/2)2t
5/4 = (1 + 0.0875/2)2t
log(5/4) = 2tlog(1 + 0.0875/2)
t = log(5/4)/2log(1 + 0.875/2)
t = 2.61 years
Keira S.
asked 04/29/20Nancy wants to invest $4000 in saving certificates that bear an interest rate of 8.75% per year, compounded semiannually. How long a time period should she choose to save an amount of $5000? (Round your answer to two decimal places.)
5000 = 4000(1 + 0.0875/2)2t
5/4 = (1 + 0.0875/2)2t
log(5/4) = 2tlog(1 + 0.0875/2)
t = log(5/4)/2log(1 + 0.875/2)
t = 2.61 years
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