A rectangular poster is 3 inches longer than it is wide. If the diagonal of the poster is √ 45 inches, what is the perimeter of the poster?

Answer 1

x^2 + (x+3)^2 = 45

x^2 + x^2 + 6x + 9 = 45

2x^2 + 6x - 36 = 0

x^2 + 3x - 18 = 0

( x + 6 )( x - 3 ) = 0

x+6=0 results in negative measures

x = 3

rectangle 3 by 6

the perimeter is 18