Venkat A. answered 08/16/20
Expert Physics Tutor with 10+ Years teaching AP Physics
Since Sue is inside the bus, from her perspective, the bus looks like it is at rest although it is moving. When she drops the ball, from her perspective, it will appear to be simply moving vertically downwards. So, one second after it is dropped, the relative velocity of the ball as measured by Sue is the acceleration due to gravity times 1 second. So it is 9.8m/s2.
As far as Bob is concerned, the ball will have two different velocities, the downward velocity and the horizontal velocity of the bus. Since these two velocities are perpendicular, the magnitude of the resultant velocity will be
v=√(9.82+302)=31.56m/s