J.R. S. answered • 04/26/20
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Fe3(PO4)2(s) <==> 3Fe2+(aq) + 2PO43-(aq)
Ksp = [Fe2+]3[PO43-]2 = 4.73x10-20
Since 1 mol Fe3(PO4)2 produces 3 mole Fe2+ and 2 mol PO42-, we can set [PO43-] = x and then [Fe2+] = 1.5x
4.73x10-20 = (1.5x)3(x)2
4.73x10-20 = 3.375x5
x5 = 1.40x10-20
x = 1.07x10-4 M
solubility of PO43- = 1.07x10-4 M and solubility of Fe2+ = 1.6x10-4 M
