
John M. answered 04/23/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
Cos(x/2) - Sin(x) = 0
√[(1+Cosx)/2] = Sinx
1+Cosx = 2Sin2
1+Cosx = 2(1-Cos2x)
1+Cosx = 2-2Cos2x
2Cos2x + Cosx -1 = 0
2Cosx - 1)(Cosx +1) = 0
Set each factor= 0
Cosx = 1/2 , Cosx= -1
x= π/3 or 60° and π